Question:LCM program in c with two numbers 

Answer 
#include<stdio.h>
int main(){
  int n1,n2,x,y;
  printf("\nEnter two numbers:");
  scanf("%d %d",&n1,&n2);
  x=n1,y=n2;
  while(n1!=n2){
      if(n1>n2)
           n1=n1-n2;
      else
      n2=n2-n1;
  }
  printf("L.C.M=%d",x*y/n1);
  return 0;
}
Alternate Solution:
#include<stdio.h>

int lcm(int,int);

int main(){
    int a,b,l;

    printf("Enter any two positive integers ");
    scanf("%d%d",&a,&b);
 
    if(a>b)
         l = lcm(a,b);
    else
         l = lcm(b,a);
   
    printf("LCM of two integers is %d",l);

    return 0;
}

int lcm(int a,int b){
  
    int temp = a;

    while(1){
         if(temp % b == 0 && temp % a == 0)
             break;
         temp++;
    }

   return temp;
}
 

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