Question:A and B can do a piece of work in 12 days ; B and C can do it in 15 days ; A and C can do it in 20 days. In how many days will A, B and C finish it, working all together ?
Also, find the number of days taken by each to finish it working alone.
Answer (A + B)'s 1 day's work` = 1/12;` (B + C)' s 1 day's work` = 1/15`
and (A + C)'s 1 day's work` = 1/20`
Adding, we get : 2 (A + B + C)'s 1 day's work
`= (1/12 + 1/15 + 1/20) = 1/5.`
:. (A + B + C)' s 1 day's work` = 1/10`
Thus A,B and C together can finish the work in 10 days.
Now A's 1 day's work
= [(A + B + C)'s 1 day's work] - [(B + C) 's 1 day's work]
`= (1/10 - 1/15) = 1/30`
A alone can finish the work in 30 days.
Similarly, B's 1 day's work` = (1/10 - 1/20) = 1/20`
:. B alone can finish the work in 20 days.
And C's 1 day's work` = (1/10 - 1/12) = 1/60.
:. C alone can finish the work in 60 days.