Question:Ramu was 4 times as old as his as his son 8 years age. After 8 years, Ramu will be twice as old his son. What are their present ages? 

Answer Let son's age 8 years ago be x years. Then, Ramu's age at that time = 4x years. Son's age after 8 years = (x + 8) + 8 = (x + 16) years. Ramu's age after 8 years = (4x + 8) + 8 =(4x + 16) years. `:.` 2 (x + 16) = 4x + 16 or x = 8 `:.` Son's present age = (x + 8) = (8 + 8) =16 years. `:.` Ramu's present age =(4x + 8) =(4 x 8 +8) =40 years. 

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Ramu was 4 times as old as his as his son 8 years age. After 8 years, Ramu will be twice as old his son. What are their present ages?
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