Question:`(x^b/x^c)^ ((b^2 + c^2 + bc))` x `(x^c/x^a)^ ((c^2 + a^2 + ca))` x `(x^a/x^b)^ ((a^2 + b^2 + ab))` 

Answer =`(x^(b - c))^((b^2 + c^2 + bc))` x `(x^(c - a))^((c^2 + a^2 + ca))` x `(x^(a - b))^((a^2 + b^2 + ab))` =`x^((b - c)(b^2 + c^2 + bc))` x `x^((c - a)(c^2 + a^2 + ca))` x `x^((a - b)(a^2 + b^2 + ab))` = `x^((b^3 - c^3))` x `x^((c^3 - a^3))` x `x^((a^3 - b^3))` =`x^((b^3 - c^3) + (c^3 - a^3) + (a^3 - b^3))` =`x^0` =1 

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`(x^b/x^c)^ ((b^2 + c^2 + bc))` x `(x^c/x^a)^ ((c^2 + a^2 + ca))` x `(x^a/x^b)^ ((a^2 + b^2 + ab))`
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