Answer `1/(x^2 - 3x + 2) + 1/(x^2 - 4x + 3) + 1/(x^2 - 5x + 4)`
`= 1/(x^2 - 2x - x + 2) + 1/(x^2 - 3x - x + 3) + 1/(x^2 - 4x - x + 4)`
`= 1/(x(x - 2) - 1(x - 2)) + 1/(x(x - 3) - 1(x - 3)) `
`+ 1/(x(x - 4) - 1(x - 4))`
`= 1/((x - 2)(x - 1)) + 1/((x - 3)(x - 1)) + 1/((x - 4)(x - 1))`
`= ((x - 3)(x - 4) + (x - 2)(x - 4) + (x - 2)(x - 3))/((x - 1)(x - 2)(x - 3)(x - 4))`
`= (x^2 - 7x + 12 + x^2 - 6x + 8 + x^2 - 5x + 6)/((x - 1)(x - 2)(x - 3)(x - 4))`
উত্তর: `= (3x^2 - 18x + 26)/((x - 1)(x - 2)(x - 3)(x - 4))`