যোগ নির্ণয় কর ৩ ছ 1 x 2 1 4 x2, বীজগণিতীয় ভগ্নাংশ, গণিত

Question:যোগ নির্ণয় কর:

 ৩.ছ. `1/(x - 2) + 1/(x + 2) + 4/(x^2 - 4)`

    জ.` 1/(x^2 - 1) + 1/(x^4 - 1) + 4/(x^8 - 1)`

Answer ছ.`1/(x - 2) + 1/(x + 2) + 4/(x^2 - 4)`

  `= (1(x + 2) + 1(x - 2))/((x - 2)(x + 2)) + 4/(x^2 - 4)`

  `= (x + 2 + x - 2)/((x - 2)(x + 2)) + 4/(x^2 - 4)`

  `= (2x)/(x^2 - 4) + 4/(x^2 - 4)`

  `= (2x + 4)/(x^2 - 4)`

  `= (2(x + 2))/((x - 2)(x + 2))`

  `= 2/(x - 2)`

  উত্তর:  `= 2/(x - 2)`


 জ. ` 1/(x^2 - 1) + 1/(x^4 - 1) + 4/(x^8 - 1)`

      `= 1/(x^2 - 1) + 1/(x^2 - 1)(x^2 + 1)) + 4/(x^8 - 1)`

      `= (x^2 + 1 + 1)/((x^2 - 1)(x^2 + 1)) + 4/(x^8 - 1)`

     `= (x^2 + 2)/(x^4 - 1) + 4/((x^4 + 1)(x^4 - 1))`

     `= ((x^2 + 2)(x^4 + 1) + 4)/((x^4 + 1)(x^4 - 1))`

     `= (x^6 + x^2 + 2x^4 + 2 + 4)/((x^4)^2 - 1^2)`

     `= (x^6 + 2x^4 + x^2 + 6)/(x^8 - 1)`

    উত্তর:  `= (x^6 + 2x^4 + x^2 + 6)/(x^8 - 1)`

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jog nirony karo: ৩.cho. `1/(x - 2) + 1/(x + 2) + 4/(x^2 - 4)` ja.` 1/(x^2 - 1) + 1/(x^4 - 1) + 4/(x^8 - 1)`

Question:যোগ নির্ণয় কর: ৩.ছ. `1/(x - 2) + 1/(x + 2) + 4/(x^2 - 4)` জ.` 1/(x^2 - 1) + 1/(x^4 - 1) + 4/(x^8 - 1)`