Question:In the triangle ABC, the angle B=`90^0`, the angle A=`42^0` and AC=10 cm. Find the length of BC.
Answer Considering the angle A, the side BC is the opposite side and AC is the hypotenuse. Therefore sin `42^0`=`BC/10` `:.` CB=10 sin `42^0` cm = `10 xx 0.6691 cm = 6.691 cm` = 6.69 cm (correct to 3 sig. fig.).
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In the triangle ABC, the angle B=`90^0`, the angle A=`42^0` and AC=10 cm. Find the length of BC.