Question:What number must be added to (`x^2` +6x) to make the result a perfect square? 

Answer (`x^2` + 6x) =`x^2` + `2.x.3` + `3^2` - 9 =`(x+3)^2` - 9 [here `(x+3)^2` is perfect square ] `:.` to make (`x^2` +6x) perfect , 9 must be added 

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What number must be added to (`x^2` +6x) to make the result a perfect square?
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