what will be output when you execute following c code define print..., Control Structure, Adv C

Question:What will be output when you will execute following c code?

#define PRINT printf("Star Wars");printf(" Psycho");
#include<stdio.h>
void main(){
    int x=1;
    if(x--)
         PRINT
    else
         printf("The Shawshank Redemption");
}

Choose all that apply:

+ Explanation

PRINT is macro constant. Macro PRINT will be replaced by its defined statement just before the actual compilation starts. Above code is converted as:

void main(){
    int x=1;
    if(x--)
         printf("Star Wars");
printf(" Psycho");
    else
         printf("The Shawshank Redemption");
}

If you are not using opening and closing curly bracket in if clause, then you can write only one statement in the if clause. So compiler will think: (i)

if(x--)
    printf("Star Wars");

It is if statement without any else. It is ok. (ii)

printf(" Psycho");

It is a function call. It is also ok (iii)

else
         printf("The Shawshank Redemption");

You cannot write else clause without any if clause. It is cause of compilation error. Hence compiler will show an error message: Misplaced else.

Question:What will be output when you will execute following c code?
#define PRINT printf("Star Wars");printf(" Psycho"); #include<stdio.h> void main(){ int x=1; if(x--) PRINT else printf("The Shawshank Redemption"); }
Choose all that apply:

A Stars Wars Psycho

B The Shawshank Redemption

C Warning: Condition is always true

D Warning: Condition is always false

E Compilation error

E

Question:What will be output when you will execute following c code?#define PRINT printf("Star Wars");printf(" Psycho"); #include<stdio.h> void main(){ int x=1; if(x--) PRINT else printf("The Shawshank Redemption"); } Choose all that apply: