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Question:Consider the following code:string s1 = "Old Value";
string s2 = s1;
s1 = "New Value";
Console.WriteLine(s2);
What will be the output printed, and why?

A "New Value", because string is a reference type. 
B "Old Value", because string is a value type. 
C "New Value", because string is a value type. 
D "Old Value", because string is a reference type 
E "Old Value", because string is a reference type which is treated as a special case by the assignment operator.

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Question:Consider the following code:string s1 = "Old Value"; string s2 = s1; s1 = "New Value"; Console.WriteLine(s2); What will be the output printed, and why?

A "New Value", because string is a reference type.

B "Old Value", because string is a value type.

C "New Value", because string is a value type.

D "Old Value", because string is a reference type

E "Old Value", because string is a reference type which is treated as a special case by the assignment operator.

E

Question:Consider the following code:
string s1 = "Old Value"; string s2 = s1; s1 = "New Value"; Console.WriteLine(s2);
What will be the output printed, and why?