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Question:How will you count the odd numbers from the array shown below using LINQ in .Net framework 4.0?

int[]numbers={5,4,1,3,9,8,6,7,2,0};

A int findoddNumbers = numbers.Count(n => n % 2 == 1); 
B int findoddNumbers = numbers.Count( n % 2 == 1); 
C int findoddNumbers = (from number in numbers where numbers%2==1 select Count()); 
D int findoddNumbers = (from number in numbers where number%2==1 select numbers).Count();

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+ AnswerA D

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Question:How will you count the odd numbers from the array shown below using LINQ in .Net framework 4.0? int[]numbers={5,4,1,3,9,8,6,7,2,0};

A int findoddNumbers = numbers.Count(n => n % 2 == 1);

B int findoddNumbers = numbers.Count( n % 2 == 1);

C int findoddNumbers = (from number in numbers where numbers%2==1 select Count());

D int findoddNumbers = (from number in numbers where number%2==1 select numbers).Count();

A D