Question:What is the greatest number of three digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?
A 975
B 996
C 939
D 903
/49
+ Answer
A
+ Explanationsolution:
Greatest number of 3 digits is 999.
L.C.M. of `6, 9 and 12 =36`.
On dividing 999 by 36, remainder obtained is 27.
`:.` Greatest number of 3 digits divisible by `6, 9, 12 = (999 - 27) = 972`.
`:.` Required number = `(972 + 30) = 975`.