Question:The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18, is :
+ Explanationsolution:
L.C.M. of `6, 9, 15, 18 is 90`.
Let required number be `90k + 4`, which is a multiple of 7.
Letast value of k for which `(90k + 4 )`is divisible by 7 is k=4.
`:.` Required number = `90 xx 4 + 4 = 364`.