Question:The least number which when divided by 5, 6, 8, 9 and 12 leaves a remainder 1 in each case, but when divided by 13 leaves no remainder, is :
A 361
B 721
C 1801
D 3601
/49
+ Answer
D
+ Explanationsolution:
L.C.M. of `5, 6, 8, 9, 12 = 360`.
`:.` Required number is of the form 360k + 1.
Least value of k for which `360k + 1` is divisible by 13 is k = 10.
`:.` Required number = `(360 xx 10 +1) = 3601`.