Question:A can do a piece of work in 14 days which B can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days to complete the work is :
+ Explanationsolution:
B's 3 day's work =`(1/21 xx 3)`
= `1/7`.
Remaining work =`(1 - 1/7)`
= `6/7`
`(A + B)`'s 1 day's work = `(1/14 + 1/21)`
=`5/42`.
Now, `5/42` work is done by A & B in 1 day.
`:. 6/7` work in done by A & B in `(42/5 xx 6/7)`
=`36/5` days.
`:.` Total time taken = `(3 + 36/5)` days
= `10 1/5` days.