Question:Give that`(1^2+2^2+3^2+...10^2)=385`,than the value of `(2^2+4^2+6^2+...+20^2)` is equal to : 

A 770 
B 1540 
C 1155 
D `(385)^2` 

+ Answer
B 

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Irin Moni

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