Question:One test tube contains some acid and another test tube contains an equal quantity o f water. To prepare a soluation ,`20`grams of the  acid is poured into the second test tube .Then two thirds of the so formed solition is poured from the second tube into the first.If the fluid in the first test tube is four times that in the second ,what quantity of water was taken intially, 

A `40 grams` 
B `60 grams` 
C `80 grams` 
D `100 grams` 

+ Answer
A 

+ Explanation
Suppose    each tube contains x gms initially.

`4[1/3(x + 20)]`

`= x + 2/3 (x + 20)`

or `2/3 (x + 20) = x`

or` x/3 = 40/3`

`:. x = 40`

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