Question:A sum of money at compound interest amounts to thrice itself in `3` years. In how many years will it be `9` times itself ? 

A `12` 
B `9` 
C `6` 
D `8` 

+ Answer
C 

+ Explanation
`p (1 + R/100)^3`

`= 3p ⇒ (1 + R/100)^3 = 3`

Let` p(1 + R/100)^n`

`= 9p ⇒ (1 + R/100)^n = 9`

`:. (1 + R/100)^n = 3^2`

`= [(1 + R/100)^3]^2`

`= (1 + R/100)^6`

Hence,n` = 6 `years.

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Irin Moni

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