Question:The radius of a wife is decreased to one third and its volume remains the same. The new length is how many times the original length ? 

A `1 times` 
B `3 times` 
C `6 times` 
D `9 times` 

+ Answer
D 

+ Explanation
Let, original radius = r and original length = h.

New radius`= (r/3)` and let new length = H.

Then, `π r^2 h = π (r/3)^2 xx H or H = 9h.`

+ Report

Irin Moni

Editor, VCampus

Your Name

Your Email

Type of Report
Spelling MistakeIncorrect AnswerGrammar MistakeContent MissingImproper Text FormatInsufficient AnswerDuplicate QuestionImproper Sentence StructureImproper Equation/FormulaOther

Description