Question:A spherical ball of lead, `3` cm in diameter is melted and recast into three spherical balls. The diameter of two of these are `1.5` cm and `2` cm respectively. The diameter of the third ball is :
A `2.66 cm`
B `2.5 cm`
C `3 cm`
D `3.5 cm`
+ Explanation`4/3 π xx (3/4)^3 + 4/3 π xx (1)^3 + 4/3 π xx x^3`
`= 4/3 π xx (3/2)^3`
`or 27/64 + 1 + x^3`
`= 27/8`
`or x^3 = 125/64`
`= (5/4)^3`
`or x = 5/4.`
:. Radius of the third ball is `5/4 cm`.
Hence, the diameter of this ball is `5/2 cm = 2.5 cm.`