Question:A cylindrical tub of radius `12` cm contains water upto a depth of `20` cm. A spherical iron ball is dropped into the tub and the level of water is raised by`6.75`cm. The radius of the ball is : 

A `4.5 cm` 
B `6 cm` 
C `7.25 cm` 
D `9 cm` 

+ Answer
D 

+ Explanation
volume of ball = volume of water displaced by it

`:. 4/3 π R^3`

`= π xx 12 xx 12 xx 6.75 ⇒ R^3`

`= 9 xx 9 xx 9 or R = 9 cm.`

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Irin Moni

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