Question:If `log_10^2 = 0.3010` and `log_10^3 = 0.4771,` then the value of `log_10 1.5`is 

A `0.7161` 
B `0.1761` 
C `0.7116` 
D `0.7611` 

+ Answer
B 

+ Explanation
`log_10^(1.5)`

`= log_10 (3/2)`

`= log_10^3 - log_10^2`

`= (0.4771 - 0.3010)`

`= 0.1761.`

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Irin Moni

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