Question:If`log_10 2 = 0.3010`, the value of `log_10 80`is : 

A `1.9030` 
B `1.6020` 
C `3.9030` 
D None of these 

+ Answer
A 

+ Explanation
`log_10 80`

`= log_10 (8 xx 10)`

`= log_10 8 + log_10 10`

`= log_10 2^3 + 1`

`= (3 log_10 2) + 1`

`= (3 xx 0.3010) + 1`

`= 1.9030`

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Irin Moni

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