Question:If log x + log y = log (x + y), then : 

A `x = y` 
B `xy = 1` 
C `y = (x - 1)/x` 
D `y = x/(x - 1)` 

+ Answer
D 

+ Explanation
`log x + log y`

`= log (x + y) ⇒ log (x + y)`

`= log (xy)`

`:. x + y = xy`

`or y(x - 1)`

`= x or y = x/(x - 1)`

+ Report

Irin Moni

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