Question:Ramlal divided two sums of money among his four sons Anil, Rahul, Deepak and Sanjeev. The first sum is divided in the ratio `4 : 3 : 2 : 1` and second in the ratio `5 : 6 : 7 : 8`. If the second sum is twice the first, the largest total is received by :
+ ExplanationLet their parts in first sum be `4x, 3x, 2x` and `x`and
let their parts in second sum be `5y, 6y, 7y` and `8y`.
`:. 2(4x + 3x + 2x + x) = (5y + 6y + 7y + 8y)`
or `20x = 26y` or `x = (13)/(10)y`.
`:. A = 4x + 5y`
`= 4 xx (13)/(10)y + 5y`
`= (102y)/(10)`
`= 10.2y,`
`R = 3x + 6y`
`= 3 xx (13)/(10)y + 6y`
`= (99y)/(10)`
`= 9.9y,`
`D = 2x + 7y`
`= 2 xx (13)/(10)y + 7y`
`= (96y)/(10)`
`= 9.6y,`
`S = x + 8y`
`= (13)/(10)y + 8y`
`=(93y)/(10)`
`= 9.3y`.
So, Anil received the largest total.
