Question:If the radius of a circle is decreased by `50%`, its area is reduced by :
A `25%`
B `50%`
C `75%`
D None
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+ Answer
C
+ ExplanationLet original radius be R. Then, area` = π R^2`
New radius `= 50% of R = 50/100 R = R/2.`
New area`= π xx (R/2)^2`
`= (πR^2)/4`
decrease`= (πR^2 - (π R^2)/4)`
`= (3 π R^2)/4`
:. Decrease `% = ((3 πR^2)/(4) xx 1/(π R^2) xx 100)%`
`= 75%`.