Question:If the perimeters of a square and a rectangle are the same, than the areas A and B enclosed by them would satisfy the condition :
A `A < B`
B `A <= B`
C `A > B`
D `A >= B`
/98
+ Answer
C
+ ExplanationLet side of a square = a. length of rect. = x & breadth of rect. = y.
`4a = 2 (x + y) =>(x + y)/2 = a`
Area of square` = a^2 = ((x + y)^2/2)` So, A`= ((x + y)^2/2)`
Area of rect. = xy. So, B = xy.
`(x + y)/2 > x^1/2 y^1/2` [:. A.M. > G.M.]
`=> ((x + y )^2/2)`> xy i. e.A > B.