Question:If the ratio of the areas of two squares is 9 : 1, the ratio of their perimeters is :
A `9 : 1`
B `3 : 1`
C `1 : 3`
D `3 : 4`
/98
+ Answer
B
+ ExplanationLet the sides of two squares be a and b respectively.
Then, `a^2/b^2 = 9/1`
or `(a/b)^2`
`= (3/1)^2` or `a/b = 3/1`
:. Ratio of their perimeters
`= (4a)/(4b) = a/b = 3/1`
or ` 3 : 1`