Question:The length of a rectangle is twice its breadth and one of its diagonals measure `10sqrt(5)` cm. The perimeter of the rectangle is : 

A `60 cm` 
B `50 cm` 
C `250 cm` 
D None 

+ Answer
A 

+ Explanation
Let breadth = x cm and length = 2x cm. Then,

`x^2 + (2x)^2`

`= (10sqrt(5)^2 or 5x^2`

`= 500 or x^2`

`= 100 or x = 10`

:. perimeter` = 2 (2x + x) cm`

                  `= 6x cm = 60 cm.`

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Irin Moni

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