+ ExplanationLet original radius = r.
Then, circumference = 2 π r and area `= π r^2`
New circumference
`= (150/100 xx 2 π r)`
`= 3 π r`
Let radius now be R.
`2 π R = 3 π r => R = 3r/2.`
New area` = π R^2 = π ((9r^2)/4)`
`= (9π r^2)/4`
Increase in area
`= ((9π r^2)/4 - π r^2)`
`= (5 π r^2)/4.`
:. Increase %` = ((5 π r^2)/4 xx 1/(π R^2) xx 100) %`
`= 125%`