+ Explanation`(sqrt(3))^5 xx 9^2`
`= 3^a xx 3sqrt(3) =>(31^(1∕2)^5 xx (3^2)^2`
`= 3^a xx 3^1 xx 3^(1/2)`
`:. 3^(5∕2) xx 3^4`
`= 3^a xx 3^1 xx 3^(1∕2) or 3^(5/2 + 4)`
`= 3^((a + 1 + 1/2))`
`or 3^(13∕2)`
`= 3^(a + 3/2). So, a + 3/2`
`= 13/2 or a = (13/2 - 3/2)`
`= 5 `