Let` a^2 = b^y = c^z = k` Then `a = k^(1/x), b = k^(1/y)` and `c = k^(1/z)` `b^2 = ac => k^(2/y)` ` = k^(1/z) => k^(2/y) = k^(1/x + 1/z)` `:. 2/y = 1/x + 1/z or 2/y` `= (x + z)/(xz) or y = (2xz)/(x + z)`