Question:If` [3^m -: (3^m)^2]^(1/m) = 81,` the value of x is : 

A 3 
B 6 
C - 3 
D - 6 

+ Answer
B 

+ Explanation
`[(3^m^2)/((3^m)^2)]^1/m = 81 => ((3^m^2)/(3^2m))^(1/m) = 3^4`

`or (3^(m^2 - 2m)^(1/m)`

`= 3^4 or 3^m(m - 2) . 1/m = 3^4`

`or 3^(m - 2) = 3^4 or m - 2 = 4 or m = 6`

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Irin Moni

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