+ ExplanationGiven Exp.` (2^(1/2) xx 3^(1/3) xx (2^2)^(1/4))/(2^(-1/5) xx 5^(-1/5) xx 5^(3/5)) -:
(3^(4/3) xx 5^(-7/5))/((2^2)^(-3/5) xx 2 xx 3)`
`= (2^(1/2) xx 3^(1/3) xx 2^(1/2))/(2^(-1/5) xx 5^(-1/5) xx 5^(3/5) xx (2^(-6/5) xx 2 xx 3)/(3^(4/3) xx 5^(-7/5))`
`= (2^((1/2 + 1/2 - 5/6 + 1/5 + 1)) xx 3^((1/3 + 1 - 4/3)))/(5^(- 1/5 + 3/5 - 7/5))`
`= (2 xx 3^0)/(5^(-1)`
`= 2 xx 1 xx 5 = 10`