Question:The number of grams of water needed to reduce 9 grams of shaving lotion containing 50% alcohol to a lotion containing 30% alcohol, is :
A 4
B 5
C 6
D 7
/139
+ Answer
C
+ ExplanationAlcohol in 9 gms` = (50/(100) xx 9)`
`= 4.5 gms.`
Let x gm of water be added. Then,
`(4.5)/(0 + x) xx 100`
`= 30 => 270 + 30x = 450 => x = 6 gms.`