Question: The radius of a wife is decreased to one third and its volume remains the same. The new length is how many times the original length ?
A
B
C
D
`1 times`
B
`3 times`
C
`6 times`
D
`9 times`
Note: Let, original radius = r and original length = h.
New radius`= (r/3)` and let new length = H.
Then, `π r^2 h = π (r/3)^2 xx H or H = 9h.`