Question: The areas of two concentric circles forming a ring are 154 sq. and 616 sq.cm. The breadth of the ring is :
A
`7 cm`
B
`14 cm`
C
`21 cm`
D
`28 cm`
Note: Let inner radius = r & outer radius = R.
Then,`22/7 xx r^2 = 154 or r^2`
`= (154 xx 7/22).` So, r = 7.
Also,` 22/7 xx R^2 = 616 or R^2`
`= (616 xx 7/22) or R = 14`
:. Breadth of the ring
`= (R - r) = (14 - 7) = 7 cm.`
Question: The circumference of two concentric circles forming a ring are 88 cm and 66 cm respectively. The width of the ring is :
A
`3.5 cm`
B
`10.5 cm`
C
`7 cm`
D
`14 cm`
Note: Let, inner radius = r & outer radius = R cm.
Then,` 2 xx 22/7 xx R = 88 => R`
`= (88 xx 7/44)`
`= 14 cm.`
` 2 xx 22/7 xx r = 66 => r`
`= (66 xx 7/44)`
`= 21/2 cm`
`= 10.5 cm.`
:. width of the ring
`= (14 - 10.5) cm`
`= 3.5 cm.`
Question: A circular road runs round a circular ground. If the difference between the circumference of the outer circle and inner circle is 66 metres, the width of the road is :
A
`5.25 m`
B
`7 m`
C
`10.5 m`
D
`21 m`
Note: `2 (R - r) = 60 => 2 xx 22/7 xx (R - r) = 60`
`:. (R - r) = (66 xx 7/44)`
`= 10.5 m.`
Question: The diameter of a wheel is 1.26 m. How far will it travel in 500 revolutions ?
A
2530 m
B
1980 m
C
1492 m
D
2880 m
Note: Radius of the wheel = 0.63 m.
Distance moved in 1 revolution = circumference
`= (2 xx 22/7 xx 0.63) m`
`= 3.96 m.`
Distance moved in 500 revolutions
`= (500 xx 3.96) m`
`= 1980 m`
Question: The radius of a wheel is 7 cm. How many revolutions will it make in moving 44 km ?
A
2000
B
10000
C
70000
D
100000
Note: Distance covered in 1 revolution = circumference
`= (2 xx 22/7 xx 7) cm`
`= 44 cm`
:.Number of revolutions made in moving 44 km
`= ((44 xx 1000 xx 100)/44)`
`= 100000`
Question: A toothed wheel of diameter 50 cm is attached to a smaller wheel of diameter 30 cm. How many revolutions will the smaller wheel make when the larger one makes 15 revolutions ?
A
18
B
20
C
25
D
30
Note: Distance moved by toothed wheel in 15 revolutions
`= (15 xx 2 xx 22/7 xx 25) cm.`
Distance moved by smaller wheel in 1 revolultion
`= (2 xx 22/7 xx 15) cm.`
:. Required number of revolutions
`= (15 xx 44/7 xx 25 xx 7)/(44 xx 15)`
`= 25`
Question: The diameter of the wheel of a vehicle is 1.4 m. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle (in kmph) is :
A
29.46
B
31.68
C
32.72
D
36.25
Note: Distance covered in 10 revolution
`= (10 xx 2 xx 22/7 xx 0.7) m`
`= 44 m.`
Distance covered in 5 sec.
`= 44 m.`
Speed` = (44/5 xx 60 xx 60 xx 1/1000) kmph`
`= 31.68 kmph`