Question: The greatest number that will divide 187, 233 and 279 leaving the same remainder in each case is :
A
B
C
D
30
B
36
C
46
D
56
Note: solution:
Required number = H.C.F. of (233-187),(279-233) & (279-187)
= H.C.F. of 46,46 & 92 =46.