1. Question: How many men need to be employed to complete a job in 5 days if 10 men can complete half the job in 7 days ?

    A
    7

    B
    14

    C
    28

    D
    35

    Note: 10 men can complete the job in 14 days. Less days more men `14/5 = x/10 => x = (14 xx 10)/5` `= 28`
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  2. Question: A contractor undertook to build a road in 100 days. He employed 110 men. After 45 days, he found that only `1/4` could be built. In order to complete the work in time, how many more men should be employed ?

    A
    120

    B
    160

    C
    180

    D
    270

    Note: Remaining work `= 3/4` Remaining days` = (100 - 45) = 55` Let x more men may be employed More work,more then (direct) More days, less men (indirect) Work` 1/4 : 3/4 }` Days 55 : 45 : : 110 : (110 + x) `110 + x = 3/4 xx 45 xx 110 xx 4/1 xx 1/55 = 270` `:. x = 160`
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  3. Question: 16 men complete one-fourth of a piece of work in 12 days. What is the additional number of men required to complete the work in 12 days ?

    A
    48

    B
    36

    C
    30

    D
    18

    Note: More work, more men (direct) `1/4 : 1 = 16 : 16 + x => 16/(16 + x)` `= 1/4` `:. 16 + x = 64 => x = 48`
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  4. Question: A, B and C together can do a piece of work in 20 days. After working with B and C for days, A leaves and then B and C complete the remaining work in 20 days more. In how many days, A alone could do the work ?

    A
    40

    B
    50

    C
    60

    D
    80

    Note: (b) : (A + B + C),s 8 days ' work` = (1/20 xx 8)` `= 2/5` Remaining work` = (1 - 2/5)` `= 3/5` `3/5` work is done by (b + c) in 20 days Whole work will be done by (B + C) in` (20 xx 5/3)` `= (100)/3` days :. (B + C)'s 1 days work ` = 3/100` :. A's 1 days work` = 1/20 - 3/100` `= 2/100` `= 1/50` Hence, A can finish the whole work in 50 days.
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  5. Question: A,B and C together can complete a piece of work in 10 days.All the three started working at it together and after 4 days, A left.Then,B and C together complete the work in 10 more days.A alone could complete the work in complete the work in 10 more days. A alone could complete the work in

    A
    15 days

    B
    16 days

    C
    25 days

    D
    50 days

    Note: (A + B + C)'s 4 days work` = (1/10 xx 4)` `= 2/5` Remaining work` = (1 - 2/5) = 3/5` `3/5` work is done by (B + C) in days whole work can be done by (B + C) in `((10 xx 5)/3)`days :. (B + C)'s 1 days work `= 3/50` A's 1 days work` = (1/10 - 3/50)` `= 1/25` :. A alone can finish the work in 25 days
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  6. Question: 20 men can finish a piece of work in 30 days.After how many days should 5 men leave the work so that it may be finished in 35 days ?

    A
    10

    B
    12

    C
    15

    D
    20

    Note: Suppose they leave after x days Work done in x days` = x/30` Remaining work` = (1 - x/30)` `= ((30 - x)/30)` Remaining days` = (35 - x)` 15 men's 1 days work` = (1/(20 xx 30) xx 15)` `= 1/40` `:. 1/40 (35 - x) = (30 - x)/(30) => 1050 - 30x` `= 1200 - 40x => x = 15`
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  7. Question: A man, a woman or a boy can do a piece of work in 3, 4 and 12 days respectively. How many boys must one man and one woman to do the work in one day ?

    A
    6

    B
    8

    C
    9

    D
    5

    Note: 1 man's 1 day's work` = 1/3,` 1 woman's 1 days work` = 1/4,` 1 boy's 1 day's work` = 1/12` Let x boys must be there. Then `1/3 + 1/4 + x/12` `= 1 => x = 5.`
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  8. Question: If 2 men and 3 boys can do a piece of work in 8 days. while 3 men and 2 boys can do it in 7 days, how long will 5 men and boys take to do it ?

    A
    3 days

    B
    4 days

    C
    5 days

    D
    6 days

    Note: Let 1 man's 1 day work = x and 1 boys 1 days work = y. Then, 2x + 3y `= 1/8, 3x + 2y = 1/7` Solving we get `: x = 1/28` and` y = 1/56` `:. 5x + 4y = 5/28 + 4/56` `= 14/56 = 1/4.` So, 5 men and 4 boys can finish the work in 4 days.
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  9. Question: A and B can do a work in 8 days, B and C can do the same work in 12 days.A,B and C together can finish it in 6 days.A and C together will do it in :

    A
    4 days

    B
    6 days

    C
    8 days

    D
    12 days

    Note: (A + B)'s 1 days work` 1/8`. (B + C)'s 1 day's work` = 1/12` (A + C)'s 1 day's work` = 1/x` :.2 (A + B + C)'s 1 days work` = (1/8 + 1/12 + 1/x)` `:. 1/2 (5/24 + 1/x)` `= 1/6 => 5/24 + 1/x` `= 1/3 or 1/x` `= 1/3 - 5/24` `= 1/8 => x = 8`
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  10. Question: If I would have been twice as efficient as today,then I would have finished a work in 12 days.If my efficiency is reduced to one-third of what it is at present,then in how many days,I would be able to finish the work ?

    A
    8

    B
    18

    C
    52

    D
    72

    Note: Suppose, I finish a work now in x days. With double efficiency, time taken` = x/2` days `:. x/2 = 12 => x = 24` With one third efficiency time taken = 3 x days `= 3 xx 24` days = 72 days
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