Question: A, B and C together can do a piece of work in 20 days. After working with B and C for days, A leaves and then B and C complete the remaining work in 20 days more. In how many days, A alone could do the work ?
Note: (b) : (A + B + C),s 8 days ' work` = (1/20 xx 8)`
`= 2/5`
Remaining work` = (1 - 2/5)`
`= 3/5`
`3/5` work is done by (b + c) in 20 days
Whole work will be done by (B + C) in` (20 xx 5/3)`
`= (100)/3` days
:. (B + C)'s 1 days work ` = 3/100`
:. A's 1 days work` = 1/20 - 3/100`
`= 2/100`
`= 1/50`
Hence, A can finish the whole work in 50 days.