Question: `[1/((log_a bc) + 1) + 1/((log_b ca) + 1) + 1/((log_c ab) + 1) ]` is equal to :
Note: Given Exp.
`= 1/(log_a bc + log_a a) + 1/(log_b ca + log_b b) + 1/(log_c ab + log_c c)`
`= 1/(log_a (abc)) + 1/(log_b (abc) + 1/(log_c (abc)`
`= log_abc a + log_abc b + log_abc c`
`= log_abc (abc) = 1.`