1. Question: An increase of Rs. `60` in the monthly salary of Madam made it `50%` of the monthly salary of kamal. What is Madam' s present monthly salary ?

    A
    Rs. 180`

    B
    `Rs. 240`

    C
    `Rs. 300`

    D
    Data inadequate

    Note: `M + 60` `= 50% of K.` Clearly, M cannot be determined
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  2. Question: From a container having pure milk,` 20%` is replaced by water and the process is repeated thrice. At the end of the third operation, the milk is :

    A
    `40% pure`

    B
    `50% pure`

    C
    `51.2% pure`

    D
    `58.8% pure`

    Note: Let total quantity of original milk `= 1000 gm.` Milk after first operation `= 80% of 1000` `= 800 gm.` Milk after second operation `= 80% of 800` `= 640 gm.` Milk after third operation `= 80% of 640` `= 512 gm.` :. Strength of final mixture `= 51`2%`
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  3. Question: A man bought a house for Rs.` 5` lakhs and rents it. He puts `12 1/2%` of each month's rent aside for repairs, pays Rs.`1660` as annual taxes and realises `10%` on his investment thereafter. The monthly rent of the house is :

    A
    `Rs. 5000`

    B
    `Rs. 4920`

    C
    `Rs. 2500`

    D
    `Rs. 2460`

    Note: Suppose monthly rent = Rs. x Then, `12x - (25)/2% of 12x - 1660` `⇒ 10% of 500000` `⇒ 12x - (25)/200 xx 12x - 1660` `⇒ 500000` `⇒ (21x)/2` `= 51660 or x` `= (51660 xx 2/21)` `= 4920.`
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  4. Question: In a public school, `1/5 th` of the girls and `1/4 th` of boys are under `12` years of age. If the total strength of the school is `1000` and number of girls is `2/5 th` of the total, what part of the total strength of the school is accounted for by those which are `12` years or more of age ?

    A
    `23%`

    B
    `45%`

    C
    `55%`

    D
    `77%`

    Note: Girls` = (2/5 xx 1000)` `= 400,` Boys `= 600` Under `12` years `= (1/5 xx 400 + 1/4 xx 600)` `= 230` Above `12` years `= (1000 - 230)` `= 770.` Required percentage `= (770/1000 xx 100)%` `= 77%`.
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  5. Question: The salaries of A and B together amount to Rs.`2000.` A spends `95%` of his salary and B,` 85%` of his. If now, their saving are the same, what is A's salary ?

    A
    `Rs. 1500`

    B
    `Rs. 1250`

    C
    `Rs. 750`

    D
    `Rs. 1600`

    Note: Let A's salary = x. Then, B's` = (2000 - x)` `5% of A` `= 15% of B, i. e. 5/100 x` `= 15/100 (2000 - x) or x` `= 1500.`
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  6. Question: A debtor can pay `87` paise in the rupee, but if his creditors would take `20%` of his debts he could pay them and have Rs. `42` left. His debts and assets respectively are

    A
    `Rs. 600, Rs. 522`

    B
    `Rs. 500, Rs. 521`

    C
    `Rs. 400, Rs. 520`

    D
    `Rs. 1000, Rs. 525`

    Note: Let the total debt = x. Asset with him `= 87/(100) x.` After paying `20%` of the debt, he is left with `80%` of the debt plus Rs.` 42.` `:. 80% of x + 42` `= 87/(100) x or 87/(100) x - 80/(100) x` `= 42 or x = 600.` :. Debt `= Rs. 600 &` Assets `= 87/100 xx 600` `= Rs. 522.`
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  7. Question: `300` grams of sugar solution has `40%` sugar in it.How much sugar should be added to make it `50%` in the solution ?

    A
    `10 gms`

    B
    `40 gms`

    C
    `60 gms`

    D
    `80 gms`

    Note: Sugar`= (40/100 xx 300) gms` `= 120 gms, water`= 180 gms` Let x gm sugar may be added. Then,(120 + x)/(300 + x) xx 100` `= 50 ⇒ 240 + 2x` `= 300 + x ⇒ x = 60.`
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  8. Question: The quantity of water (in ml) needed to reduce `9` ml shaving lotion containing `50%` alcohol to a lotion containing `30%`alcohol, is :

    A
    `4`

    B
    `5`

    C
    `6`

    D
    `7`

    Note: Alcohol in `9` ml `= (50/100 xx 9) ml` `= 4.5 ml`, water` = 4.5 ml.` Let the water to be added be x ml. Then,`(4.5)/(9 + x) xx 100` `= 30 ⇒ 450` `= 270 + 30x ⇒ x = 6 ml`
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  9. Question: To a sugar solution of `3` litres containing `40%` sugar, one litre of water is added. The percentage of sugar in the new solution is :

    A
    `13 1/3%`

    B
    `15%`

    C
    `30%`

    D
    `33%`

    Note: Sugar` = (40/100 xx 3) litres` `= 1.2 litres,` water`= 1.8 litres` New percentage`= (1.2/4 xx 100)%` `= 30%`
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  10. Question: The price of an article is cut by `20%`. To restore it the former value, the new price must be increased by :

    A
    `20%`

    B
    `25%`

    C
    `16 2/3%`

    D
    `24%`

    Note: Let original price`= 100`. New price`= 80` Increase on`80 = 20` Increase on`100 = (20/80 xx 100)%` `= 25%`.
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