Question: `85` kg of a mixture contains milk and water in the ratio `27 : 7`. How much more water is to be added to get a new mixture containing milk and water in the ratio `3 : 1` ?
A
B
C
D
`5` kg
B
`6.5` kg
C
`7.25` kg
D
`8` kg
Note: Milk in `85` kg `= (85 xx (27)/(34))` kg
`= (135)/2` kg.
Water in `85` kg `= (85 xx (135)/2)` kg
`= (35)/2` kg.
Let `x` kg of water be added.
`(Milk)/(Water) = 3/1`
`iff ((135)/2)/((35)/2 + x) = 3/1`
or `(135)/(35 + 2x) = 3/1`
or `6x + 105 = 135`
or `x = 5` kg.