Note: Ratio of the speeds of A and B` = 5/3 : 1 = 5 : 3.` Thus in a race of 5m, A gains 2 m over B. 2m are gained by A in a race of 5m. 80 m will be gained by A in a race of` (5/2 xx 80) m. = 200 m :. Winning post is 200 m away from the starting point

Note: A : B = 100 : 75 and B : C = 100 : 96%. :. A : C `= (A/B xx B/C)` `= (100/75 xx 100/96)` `= 100/72 = 100 : 72. :. A beats C by (100 - 72) m = 28 m.

Note: A : B = 100 : 90 and A : C = 100 : 72 B : C` = B/A xx A/C` `= 90/100 xx 100/72` `= 90/72` When by runs 90 m, C runs 72 m When B runs 100 m, C runs 72 m When B runs 100 m, C runs` (72/90 xx 100) m` `= 80 m` :. B can give C 20 m.

Note: A : B = 100 : 90, A : C = 100 : 87 `B/C = B/A xx A/C ` `= 90/100 xx 100/87 = 30/29` When B runs 180 m, C runs` (29/30 xx 180) m` `= 174 m` :.B beat C by (180 - 174) m = 6 m.

Note: A's speed` = (5 xx 5/18)1` m/sec` = 25/18` m/sec. Time taken by A to cover 100 m` = (100 xx 18/25)`sec = 72 sec. :. Time taken by A to cover 92 m in (72 + 8) sec or 80 sec. :. B's speed` = (92/80 xx 18/5)` kmph = 4.14 kmph

Note: A : B = 100 : 80 and A : C = 100 : 72 `:. B/C = (B/A xx A/C)` `= (80/100 xx 100/72)` `= 10/9 = 100/90` `= 100 : 90` :. B can give C 10 points

Note: A : B = 60 : 45 and A : C = 60 : 40. `:. B/C = (B/A xx A/C)` `= (45/60 xx 60/40)` `= 45/40 = 90/80` `= 90 : 80` :. B can give C 10 points in a game of 90.

Note: 1995 being on ordinary year, it has I odd day. So the first day will be one day beyond Sunday, i,e it will be Monday.

Note: 1994 being an ordinary year, it has I odd day. So, the day on 8th Feb, 1995 is one day beyond the day on 8th Feb, 1994. :. 8th Feb, 1995 was Wednesday. :. 8th Feb, 1994 was Tuesday.

Note: 1992 being a leap year, it has 2 odd days. So the day on may, 1993 is 2 days beyond the day on May 6, 1992. But, on May 6, 1993 it was Thursday. So, on May 6, 1992 it was Tuesday.