Note: Counting the number of days after 3rd November, 1994 we have Nov. Dec. Jan. Feb. March 27 + 31 + 31 + 28 + 20 = 137 days = 19 weeks + 4 days :. November of odd days = 4 :. The day on 3rd November, 1994 is (7 - 4) days beyond the day on 20th March, 1995. So, the required day is Thursday.

Note: Each day of the week is repeated after 7 days :. After 63 days, it will be Tuesday. :. After 62 days, it will be Monday.

Note: This begin a leap year, none of the next 3 years is a leap year. So, the day of the week will be 3 days beyond Wednesday. :. The day after 3 years will be Saturday.

Note: Starting with 1996, we go on counting the number of odd days till the sum is divisible by 7. Year 1996 1997 1998 1999 2000 odd days 2 1 1 1 2 = 7 odd days i,e o odd day. :. Calendar for 2001 will be the same as that of 1995.

Note: Jan Feb March 30 + 28 + 15 = 73 days

Note: Do yourself. It was Thursday

Note: Do yourself. It was Tuesday

Note: 1600 years contain 0 odd day. 300 years contain 1 odd day. 100 years contain 5 odd days. :. 2000 years contain (0 + 1 + 5) odd days = 6 odd days. 1st Jan, 2001 has one odd day. :. Total number of odd days upto 1st Jan, 2001 = 7 odd days = 0 odd days. :. The day will be Sunday

Note: Total number of odd days from 1st Jan, 1991 to 1st Jan, 1998 Year 1991 1992 1993 1994 1995 1996 1997 Odd days 1 + 2 + 1 + 1 + 1 + 2 + 1 = 9 odd days i,e 2 odd days :. The day is 2 days beyond the day on 1st Jan, 1991. i,e. The required day must be Thursday.

Note: Find the day on 1st April, 1994. 1600 years contain 0 odd day 300 years contain 1 odd day 93 years = (23 leap years + 70 ordinary years ) = (46 + 70) odd days = 4 odd days. Number of days upto 1st April, 1994 Jan Feb March April 31 + 28 + 31 + 1 = 91 days = 0 odd day. :. Total number of odd days = (0 + 1 + 4 + 0) = 5 odd day. :. Day on 1st April 1994 is 'Friday' :. Sunday was on 3rd April, 1994. Thus, Sunday fell on 3rd, 10th, 17th, & 24th.