Question:What will be the output of the program? 
public class Test 
{
    public static int y;
    public static void foo(int x) 
    {
        System.out.print("foo ");
        y = x;
    }
    public static int bar(int z) 
    {
        System.out.print("bar ");
        return y = z;
    }
    public static void main(String [] args ) 
    {
        int t = 0;
        assert t > 0 : bar(7);
        assert t > 1 : foo(8); /* Line 18 */
        System.out.println("done ");
    }
} 

A bar 
B bar done 
C foo done 
D Compilation fails 

+ Answer
D 

+ Explanation
The foo() method returns void. It is a perfectly acceptable method, but because it returns void it cannot be used in an assert statement, so line 18 will not compile.

+ Report

Suman Chowdhury

Editor, VCampus

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