what will be the output of program public class rtexcept static..., Exception Handling, Java

Question:What will be the output of the program?public class RTExcept 
{
    public static void throwit () 
    {
        System.out.print("throwit ");
        throw new RuntimeException();
    }
    public static void main(String [] args) 
    {
        try 
        {
            System.out.print("hello ");
            throwit();
        }
        catch (Exception re ) 
        {
            System.out.print("caught ");
        }
        finally 
        {
            System.out.print("finally ");
        }
        System.out.println("after ");
    }
}

A hello throwit caught 
B Compilation fails 
C hello throwit RuntimeException caught after 
D hello throwit caught finally after

/10

+ AnswerD

+ ExplanationThe main() method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal.

A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.

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