what will be the output of program public class myprogram static..., Exception Handling, Java

Question:What will be the output of the program?public class MyProgram 
{
    public static void main(String args[])
    {
        try 
        {
            System.out.print("Hello world ");
        }
        finally 
        {
            System.out.println("Finally executing ");
        }
    }
}

A Nothing. The program will not compile because no exceptions are specified. 
B Nothing. The program will not compile because no catch clauses are specified. 
C Hello world. 
D Hello world Finally executing

/10

+ AnswerD

+ ExplanationFinally clauses are always executed. The program will first execute the try block, printing Hello world, and will then execute the finally block, printing Finally executing.

Option A, B, and C are incorrect based on the program logic described above. Remember that either a catch or a finally statement must follow a try. Since the finally is present, the catch is not required.

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Question:What will be the output of the program?public class MyProgram { public static void main(String args[]) { try { System.out.print("Hello world "); } finally { System.out.println("Finally executing "); } } }

A Nothing. The program will not compile because no exceptions are specified.

B Nothing. The program will not compile because no catch clauses are specified.

C Hello world.

D Hello world Finally executing

D

Question:What will be the output of the program?
public class MyProgram { public static void main(String args[]) { try { System.out.print("Hello world "); } finally { System.out.println("Finally executing "); } } }