Question:C program to convert binary to octal 

#include<stdio.h>
#define MAX 1000
int main(){
   
    char octalNumber[MAX];
    long int i=0;

    printf("Enter any octal number: ");
    scanf("%s",octalNumber);

    printf("Equivalent binary value: ");
    while(octalNumber[i]){
        switch(octalNumber[i]){
             case '0': printf("000"); break;
             case '1': printf("001"); break;
             case '2': printf("010"); break;
             case '3': printf("011"); break;
             case '4': printf("100"); break;
             case '5': printf("101"); break;
             case '6': printf("110"); break;
             case '7': printf("111"); break;
             default:  printf("\nInvalid octal digit %c ",octalNumber[i]); return 0;
    }
    i++;
 }

    return 0;
}
Sample output:
Enter any octal number: 123
Equivalent binary value: 001010011

Question:C code to convert octal number to decimal number 

#include<stdio.h>
#include<math.h>

int main(){
   
    long int octal,decimal =0;
    int i=0;

    printf("Enter any octal number: ");
    scanf("%ld",&octal);

    while(octal!=0){
         decimal = decimal + (octal % 10) * pow(8,i++);
         octal = octal/10;
    }

    printf("Equivalent decimal value: %ld",decimal);

   return 0;
}
Sample output:
Enter any octal number: 346
Equivalent decimal value: 230

Question:C program to change octal to decimal 

#include<stdio.h>

int main(){
   
    long int octalNumber;

    printf("Enter any octal number: ");
    scanf("%o",&octalNumber);

    printf("Equivalent decimal number is: %d",octalNumber);

    return 0;
}
Sample output:
Enter any octal number: 17
Equivalent decimal number is: 15

Question:C program for hexadecimal to binary conversion 

#include<stdio.h>
#define MAX 1000

int main(){
    char binaryNumber[MAX],hexaDecimal[MAX];
    long int i=0;

    printf("Enter any hexadecimal number: ");
    scanf("%s",hexaDecimal);

    printf("\nEquivalent binary value: ");
    while(hexaDecimal[i]){
         switch(hexaDecimal[i]){
             case '0': printf("0000"); break;
             case '1': printf("0001"); break;
             case '2': printf("0010"); break;
             case '3': printf("0011"); break;
             case '4': printf("0100"); break;
             case '5': printf("0101"); break;
             case '6': printf("0110"); break;
             case '7': printf("0111"); break;
             case '8': printf("1000"); break;
             case '9': printf("1001"); break;
             case 'A': printf("1010"); break;
             case 'B': printf("1011"); break;
             case 'C': printf("1100"); break;
             case 'D': printf("1101"); break;
             case 'E': printf("1110"); break;
             case 'F': printf("1111"); break;
             case 'a': printf("1010"); break;
             case 'b': printf("1011"); break;
             case 'c': printf("1100"); break;
             case 'd': printf("1101"); break;
             case 'e': printf("1110"); break;
             case 'f': printf("1111"); break;
             default:  printf("\nInvalid hexadecimal digit %c ",hexaDecimal[i]); return 0;
         }
         i++;
    }

    return 0;
}
Sample output:
Enter any hexadecimal number: 2AD5
Equivalent binary value: 0010101011010101

Question:C program c program to convert binary to octal 

#include<stdio.h>
int main(){
   
    long int binaryNumber,octalNumber=0,j=1,remainder;

    printf("Enter any number any binary number: ");
    scanf("%ld",&binaryNumber);

    while(binaryNumber!=0){
         remainder=binaryNumber%10;
        octalNumber=octalNumber+remainder*j;
        j=j*2;
        binaryNumber=binaryNumber/10;
    }

    printf("Equivalent octal value: %lo",octalNumber);

    return 0;
}
Sample output:
Enter any number any binary number: 1101
Equivalent hexadecimal value: 15

Question:C code for how to convert large binary to octal 

#include<stdio.h>
#define MAX 1000

int main(){
   
    char binaryNumber[MAX],octalNumber[MAX];
    long int i=0,j=0;

    printf("Enter any number any binary number: ");
    scanf("%s",binaryNumber);

    while(binaryNumber[i]){
      binaryNumber[i] = binaryNumber[i] -48;
      ++i;
    }

    --i;
    while(i-2>=0){
    octalNumber[j++] = binaryNumber[i-2] *4 +  binaryNumber[i-1] *2 + binaryNumber[i] ;
    i=i-3;
    }

    if(i ==1)
      octalNumber[j] = binaryNumber[i-1] *2 + binaryNumber[i] ;
    else if(i==0)
      octalNumber[j] =  binaryNumber[i] ;
    else
      --j;

    printf("Equivalent octal value: ");
    while(j>=0){
      printf("%d",octalNumber[j--]);
    }

    return 0;
}
Sample output:
Enter any number any binary number: 1111111111111111111
1111111111111111111111111111111111111111111111111111111
1111111111111111111111111111111111111111111111111111111
1111111111111111111111111111111111111111111111111111111
1111111111111111111111111111111111111111111111111111111
11111111
Equivalent octal value: 3777777777777777777777777777777
7777777777777777777777777777777777777777777777777777

Question:C code for binary to decimal conversion 

#include<stdio.h>

int main(){
   
    long int binaryNumber,decimalNumber=0,j=1,remainder;

    printf("Enter any number any binary number: ");
    scanf("%ld",&binaryNumber);

    while(binaryNumber!=0){
         remainder=binaryNumber%10;
        decimalNumber=decimalNumber+remainder*j;
        j=j*2;
        binaryNumber=binaryNumber/10;
    }

    printf("Equivalent decimal value: %ld",decimalNumber);

    return 0;
}
Sample output:
Enter any number any binary number: 1101
Equivalent decimal value: 13

Question:C program for hexadecimal to binary conversion 

#include<stdio.h>
int main(){
   
    long int binaryNumber,hexadecimalNumber=0,j=1,remainder;
   
    printf("Enter any number any binary number: ");
    scanf("%ld",&binaryNumber);
   
    while(binaryNumber!=0){
    remainder=binaryNumber%10;
    hexadecimalNumber=hexadecimalNumber+remainder*j;
        j=j*2;
        binaryNumber=binaryNumber/10;
      }
   
    printf("Equivalent hexadecimal value: %lX",hexadecimalNumber);

    return 0;
}
Sample output:
Enter any number any binary number: 1101
Equivalent hexadecimal value: D

Question:How to convert large binary number to hexadecimal 

#include<stdio.h>
#define MAX 1000

int main(){

   char binaryNumber[MAX],hexaDecimal[MAX];
   int temp;
   long int i=0,j=0;
  
   printf("Enter any number any binary number: ");
   scanf("%s",binaryNumber);

   while(binaryNumber[i]){
      binaryNumber[i] = binaryNumber[i] -48;
      ++i;
   }

   --i;
   while(i-2>=0){
       temp =  binaryNumber[i-3] *8 + binaryNumber[i-2] *4 +  binaryNumber[i-1] *2 + binaryNumber[i] ;
       if(temp > 9)
            hexaDecimal[j++] = temp + 55;
       else
            hexaDecimal[j++] = temp + 48;
       i=i-4;
   }

   if(i ==1)
      hexaDecimal[j] = binaryNumber[i-1] *2 + binaryNumber[i] + 48 ;
   else if(i==0)
      hexaDecimal[j] =  binaryNumber[i] + 48 ;
    else
      --j;

   printf("Equivalent hexadecimal value: ");
   while(j>=0){
      printf("%c",hexaDecimal[j--]);
   }

   return 0;
}
Sample output:
Enter any number any binary number: 1010011011100011110
001001111011110001000100011101110111011110
Equivalent hexadecimal value: 14DC789EF111DDDE

Question:C code for sum of two binary numbers 

#include<stdio.h>

int main(){

    long int binary1,binary2;
    int i=0,remainder = 0,sum[20];

    printf("Enter any first binary number: ");
    scanf("%ld",&binary1);
    printf("Enter any second binary number: ");
    scanf("%ld",&binary2);

    while(binary1!=0||binary2!=0){
         sum[i++] =  (binary1 %10 + binary2 %10 + remainder ) % 2;
         remainder = (binary1 %10 + binary2 %10 + remainder ) / 2;
         binary1 = binary1/10;
         binary2 = binary2/10;
    }

    if(remainder!=0)
         sum[i++] = remainder;

    --i;
    printf("Sum of two binary numbers: ");
    while(i>=0)
         printf("%d",sum[i--]);

   return 0;
}
Sample output:
Enter any first binary number: 1100011
Enter any second binary number: 1101
Sum of two binary numbers: 1110000