the base of a triangular field is three times its altitude, Area, General Mathematics

Question:The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

Answer Area of the field` = (Total cost)/(Rate)`

                     `= ((333.18)/(24.68))` hectares

                     = 13.5 hectares

  
     `= (13.5 xx 10000) m^2`

     `= 135000 m^2`

Let, altitude = x metres and base = 3x metres.

Then,` 1/2 xx 3x xx x = 135000 or x^2`

  `= 90000 or x = 300.`

:. Base = 900 m & Altitude = 300 m.

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The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

Question:The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

Answer Area of the field` = (Total cost)/(Rate)` `= ((333.18)/(24.68))` hectares = 13.5 hectares `= (13.5 xx 10000) m^2` `= 135000 m^2` Let, altitude = x metres and base = 3x metres. Then,` 1/2 xx 3x xx x = 135000 or x^2` `= 90000 or x = 300.` :. Base = 900 m & Altitude = 300 m.