Question:x = 3, y = 5 হলে-------- ক. `(x + y)^2` = কত ? 2 খ. `((x + y)^2 + (x - y)^2)/4` এর মান নির্ণয় কর । 4 গ. দেখা্ও যে, `y^2 - x^2 = (x + y) (y - x)` 4 

Answer ক. দেওয়া আছে,` x = 3, y = 5` `:. (x + y)^2 = (3 + 5)^2` ` = (8)^2 = 8 xx 8` `= 64` খ. এখানে, `((x + y)^2 + (x - y)^2)/4` `= (64 + (3 - 5)^2)/4`['ক' হতে `(x + y^2)`এর মান বসিয়ে] `= (64 + (-2)^2)/4` `= (64 + (- 2) xx (- 2))/4` `= (64 + 4)/4` `= 68/4` `= 17` গ. এখানে, `y^2 - x^2 = (5)^2 - (3)^2` `= 5 xx 5 - 3 xx 3 ` `= 25 - 9 = 16` এবং `(x + y) (y - x) = (3 xx 5) (5 - 3) = 8 xx 2 = 16` `:. y^2 - x^2 = (x + y) (x - y)` 

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x = 3, y = 5 hole-------- ka. `(x + y)^2` = koto ? 2 kh. `((x + y)^2 + (x - y)^2)/4` ar man nirony kar . 4 ga. dekhao je, `y^2 - x^2 = (x + y) (y - x)` 4
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